(x^3y^-1)/(x^2y^4)^3

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Solution for (x^3y^-1)/(x^2y^4)^3 equation: 


D( x )

(x^2*y^4)^3 = 0

(x^2*y^4)^3 = 0

(x^2*y^4)^3 = 0

x^6*y^12 = 0 // : y^12

x^6 = 0

x = 0

x in (-oo:0) U (0:+oo)

(x^3*y^-1)/((x^2*y^4)^3) = 0

x^-3*y^-13 = 0 // : y^-13

x^-3 = 0

x należy do O

x belongs to the empty set

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